Arshdeep Singh has a chance to create history, will become number 1 by defeating Jasprit Bumrah and Bhuvneshwar Kumar.

The four-match T20 series between India and South Africa (IND vs SA T20I) will start from Friday, November 8, the first match of which will be played at Kingsmead.

The four-match T20 series between India and South Africa (IND vs SA T20I) will start from Friday, November 8, the first match of which will be played at Kingsmead. During this T20 series, Indian team's fast bowler Arshdeep Singh can make some special records in his name. He can achieve this feat by defeating Jasprit Bumrah and Bhuvneshwar Kumar.

Chance to overtake Bumrah by taking only 3 wickets

Arshdeep Singh has so far taken 87 wickets in 56 matches for Team India in T20 International. If he takes just 3 more wickets in the T20 series against South Africa, then by doing so he will overtake Jasprit Bumrah. It is noteworthy that Bumrah has 89 wickets in his name in 70 T20 Internationals.

Currently, Bumrah is at number-3 and Arshdeep Singh is at number-4 in terms of taking most wickets for India in T20 International. In this list, Yuzvendra Chahal remains at number-1 with 96 wickets.

Arshdeep Singh will break Bhuvneshwar Kumar's great record

If 25-year-old Arshdeep Singh takes only 5 wickets in the T20 series against South Africa, then by doing so he will become the bowler with the highest T20 International wicket taker against South Africa. At present, he has 10 wickets in his name in 6 T20 Internationals against South Africa. Bhuvneshwar Kumar is at the top of this list who has taken 14 wickets in 12 matches.

Indian team for four-match T20 series against South Africa

Suryakumar Yadav (captain), Abhishek Sharma, Sanju Samson (wicketkeeper), Rinku Singh, Tilak Verma, Jitesh Sharma (wicketkeeper), Hardik Pandya, Axar Patel, Ramandeep Singh, Varun Chakraborty, Ravi Bishnoi, Arshdeep Singh, Vijaykumar Vaishakh, Avesh Khan. , Yash Dayal.